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Q1. - (Topic 3)
What is the default administrative distance of the OSPF routing protocol?
A. 90
B. 100
C. 110
D. 120
E. 130
F. 170
Answer: C
Explanation:
Default Distance Value Table This table lists the administrative distance default values of the protocols that Cisco supports: If the administrative distance is 255, the router does not believe the source of that route and does not install the route in the routing table.
Q2. - (Topic 5)
Refer to the exhibit.
The junior network support staff provided the diagram as a recommended configuration for the first phase of a four-phase network expansion project. The entire network expansion will have over 1000 users on 14 network segments and has been allocated this IP address space.
192.168.1.1 through 192.168.5.255
192.168.100.1 through 192.168.100.255
What are three problems with this design? (Choose three.)
A. The AREA 1 IP address space is inadequate for the number of users.
B. The AREA 3 IP address space is inadequate for the number of users.
C. AREA 2 could use a mask of /25 to conserve IP address space.
D. The network address space that is provided requires a single network-wide mask.
E. The router-to-router connection is wasting address space.
F. The broadcast domain in AREA 1 is too large for IP to function.
Answer: A,C,E
Explanation:
The given IP addresses of areas 1 and 3 along with network masks of /24 cannot accommodate 500 users so are inadequate, while the area 2 is having over capacity so its network mask can be reduced to /25 to accommodate the only 60 users it has.
Q3. - (Topic 7)
Two hosts are attached to a switch with the default configuration. Which statement about the configuration is true?
A. IP routing must be enabled to allow the two hosts to communicate.
B. The two hosts are in the same broadcast domain.
C. The switch must be configured with a VLAN to allow the two hosts to communicate.
D. Port security prevents the hosts from connecting to the switch.
Answer: A
Explanation: IP routing must be enables to allow the two hosts to communicate with each other with default configuration. http://www.cisco.com/c/en/us/support/docs/lan-switching/inter-vlan-routing/41860-howto-L3-intervlanrouting.html
Q4. - (Topic 3)
Which statement about IPv6 is true?
A. Addresses are not hierarchical and are assigned at random.
B. Only one IPv6 address can exist on a given interface.
C. There are 2.7 billion addresses available.
D. Broadcasts have been eliminated and replaced with multicasts.
Answer: D
Explanation:
IPv6 has three types of addresses, which can be categorized by type and scope:
Unicast addresses. A packet is delivered to one interface.
Multicast addresses. A packet is delivered to multiple interfaces.
Anycast addresses. A packet is delivered to the nearest of multiple interfaces (in terms of
routing distance).
IPv6 does not use broadcast messages.
Unicast and anycast addresses in IPv6 have the following scopes (for multicast addresses,
the scope are built into the address structure):
Link-local. The scope is the local link (nodes on the same subnet).
Site-local. The scope is the organization (private site addressing).
Global. The scope is global (IPv6 Internet addresses).
In addition, IPv6 has special addresses such as the loopback address. The scope of a
special address depends on the type of special address.
Much of the IPv6 address space is unassigned.
http://technet.microsoft.com/en-us/library/cc757359(v=ws.10).aspx
Q5. - (Topic 5)
Refer to the exhibit.
Why did the device return this message?
A. The command requires additional options or parameters
B. There is no show command that starts with ru.
C. The command is being executed from the wrong router mode.
D. There is more than one show command that starts with the letters ru.
Answer: D Explanation:
Answer D is correct because when you type the incomplete command it will not autocomplete if there is more than one option for completing the command. In this case, there is another command that also starts with “show ru”
Q6. - (Topic 5)
Refer to the exhibit.
The DHCP settings have recently been changed on the DHCP server and the client is no longer able to reach network resources. What should be done to correct this situation?
A. Verify that the DNS server address is correct in the DHCP pool.
B. Ping the default gateway to populate the ARP cache.
C. Use the tracert command on the DHCP client to first determine where the problem is located.
D. Clear all DHCP leases on the router to prevent address conflicts.
E. Issue the ipconfig command with the /release and /renew options in a command window.
Answer: E
Explanation:
A PC will retain its DHCP assigned IP address until the lease time expires, which often times is 24 hours or more. When changes are made to the DHCP server, the client should issue the ipconfig/release and then ipconfig/renew commands to obtain a new IP address lease.
Q7. - (Topic 7)
Which routing protocol has the smallest default administrative distance?
A. IBGP
B. OSPF
C. IS-IS
D. EIGRP
E. RIP
Answer: D
Explanation: http://www.cisco.com/c/en/us/support/docs/ip/border-gateway-protocol-bgp/15986-admin-distance.html Default Distance Value TableThis table lists the administrative distance default values of the protocols that Cisco supports:
Route Source Default Distance Values
Connected interface 0 Static route 1 Enhanced Interior Gateway Routing Protocol (EIGRP) summary route 5 External Border Gateway Protocol (BGP) 20 Internal EIGRP 90 IGRP 100 OSPF 110 Intermediate System-to-Intermediate System (IS-IS) 115 Routing Information Protocol (RIP) 120 Exterior Gateway Protocol (EGP) 140 On Demand Routing (ODR) 160 External EIGRP 170 Internal BGP 200 Unknown*
Q8. - (Topic 3)
On a live network, which commands will verify the operational status of router interfaces? (Choose two.)
A. Router# show interfaces
B. Router# show ip protocols
C. Router# debug interface
D. Router# show ip interface brief
E. Router# show start
Answer: A,D
Explanation:
Only two commands “show interfaces” and “show ip interface brief” reveal the status of router interfaces (up/up, for example).
Q9. - (Topic 3)
Refer to the exhibit.
The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and 208.149.23.96?
A. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
B. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10, 00:00:16, FastEthemet0/0
C. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
D. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10, 00:00:16, Serial1/0
Answer: A
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A
through FastEthernet interface. The interface cost is calculated with the formula 108 /
Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the
cost is 12 (learned from Router_A) + 1 = 13 for both subnets ->
The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps =
64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link ->
Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0.
In fact, we can quickly eliminate answers B, C and D because they contain at least one
subnet learned from Serial1/0 -> they are surely incorrect.
Q10. - (Topic 3)
The command ip route 192.168.100.160 255.255.255.224 192.168.10.2 was issued on a router. No routing protocols or other static routes are configured on the router. Which statement is true about this command?
A. The interface with IP address 192.168.10.2 is on this router.
B. The command sets a gateway of last resort for the router.
C. Packets that are destined for host 192.168.100.160 will be sent to 192.168.10.2.
D. The command creates a static route for all IP traffic with the source address
192.168.100.160.
Answer: C
Explanation:
With 160 it's actually network address of /27 so any address within the range of .160-.191 network will be sent to 192.168.10.2
Q11. - (Topic 3)
What does administrative distance refer to?
A. the cost of a link between two neighboring routers
B. the advertised cost to reach a network
C. the cost to reach a network that is administratively set
D. a measure of the trustworthiness of a routing information source
Answer: D
Reference: http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a0080094195.shtml
Administrative distance is the feature that routers use in order to select the best path when there are two or more different routes to the same destination from two different routing protocols. Administrative distance defines the reliability of a routing protocol. Each routing protocol is prioritized in order of most to least reliable (believable) with the help of an administrative distance value.
Administrative distance is the first criterion that a router uses to determine which routing protocol to use if two protocols provide route information for the same destination. Administrative distance is a measure of the trustworthiness of the source of the routing information. The smaller the administrative distance value, the more reliable the protocol.
Q12. - (Topic 3)
Which two statements describe the IP address 10.16.3.65/23? (Choose two.)
A. The subnet address is 10.16.3.0 255.255.254.0.
B. The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
C. The last valid host address in the subnet is 10.16.2.254 255.255.254.0
D. The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
E. The network is not subnetted.
Answer: B,D
Explanation:
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are 2.1 through 3.254
Q13. - (Topic 5)
Refer to the exhibit.
The network administrator is testing connectivity from the branch router to the newly installed application server. What is the most likely reason for the first ping having a success rate of only 60 percent?
A. The network is likely to be congested, with the result that packets are being intermittently dropped.
B. The branch router had to resolve the application server MAC address.
C. There is a short delay while NAT translates the server IP address.
D. A routing table lookup delayed forwarding on the first two ping packets.
E. The branch router LAN interface should be upgraded to FastEthernet.
Answer: B
Explanation:
Initially the MAC address had to be resolved, but once it is resolved and is in the ARP table of the router, pings go through immediately.
Q14. - (Topic 3)
Refer to the exhibit.
If CDP is enabled on all devices and interfaces, which devices will appear in the output of a show cdp neighbors command issued from R2?
A. R2 and R3
B. R1 and R3
C. R3 and S2
D. R1, S1, S2, and R3
E. R1, S1, S2, R3, and S3
Answer: C
Explanation:
A Cisco device enabled with CDP sends out periodic interface updates to a multicast address in order to make itself known to neighbors. Since it is a layer two protocol, these packets are not routed. So the devices detected would be immediate connected neighbors.
Q15. - (Topic 3)
An administrator is working with the 192.168.4.0 network, which has been subnetted with a /26 mask. Which two addresses can be assigned to hosts within the same subnet? (Choose two.)
A. 192.168.4.61
B. 192.168.4.63
C. 192.168.4.67
D. 192.168.4.125
E. 192.168.4.128
F. 192.168.4.132
Answer: C,D
Explanation:
Increment: 64 (/26 = 11111111.11111111.11111111.11000000)
The IP 192.168.4.0 belongs to class C. The default subnet mask of class C is /24 and it has
been subnetted with a /26 mask so we have 2(26-24).= 22.= 4 sub-networks:
1st subnet: 192.168.4.0 (to 192.168.4.63)
2nd subnet: 192.168.4.64 (to 192.168.4.127)
3rd subnet: 192.168.4.128 (to 192.168.4.191)
4th subnet: 192.168.4.192 (to 192.168.4.225)
In all the answers above, only answer C and D are in the same subnet.
Therefore only IPs in this range can be assigned to hosts.