1Z0-051 Premium Bundle

1Z0-051 Premium Bundle

Oracle Database: SQL Fundamentals I Certification Exam

4.5 
(28935 ratings)
0 QuestionsPractice Tests
0 PDFPrint version
December 4, 2024Last update

Oracle 1Z0-051 Free Practice Questions

Q1. - (Topic 1) 

Evaluate the following SQL statement: 

SQL> SELECT cust_id. cust_last_name FROM customers WHERE cust_credit_limit IN (select cust_credit_limit FROM customers WHERE cust_city='Singapore'): 

Which statement is true regarding the above query if one of the values generated by the sub query is NULL? 

A. It produces an error. 

B. It executes but returns no rows. 

C. It generates output for NULL as well as the other values produced by the sub query. 

D. It ignores the NULL value and generates output for the other values produced by the sub query. 

Answer:

Q2. - (Topic 1) 

Evaluate these two SQL statements: 

SELECT last_name, salary, hire_date FROM EMPLOYEES ORDER BY salary DESC; 

SELECT last_name, salary, hire_date FROM EMPLOYEES ORDER BY 2 DESC; 

What is true about them? 

A. The two statements produce identical results. 

B. The second statement returns a syntax error. 

C. There is no need to specify DESC because the results are sorted in descending order by default. 

D. The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement. 

Answer:

Explanation: Explanation: the two statement produce identical results as ORDER BY 2 will take the second column as sorting column. 

Incorrect Answer: Bthere is no syntax error Cresult are sorted in ascending order by default DORDER BY 2 will take the second column as sorting column. Refer: Introduction to Oracle9i: SQL, Oracle University Study Guide, 2-22 

Q3. - (Topic 2) 

The EMPLOYEES table has these columns: 

LAST NAMEVARCHAR2(35) SALARYNUMBER(8,2) HIRE_DATEDATE 

Management wants to add a default value to the SALARY column. You plan to alter the table by using this SQL statement: 

ALTER TABLE EMPLOYEES MODIFY (SALARY DEFAULT 5000); 

What is true about your ALTER statement? 

A. Column definitions cannot be altered to add DEFAULT values. 

B. A change to the DEFAULT value affects only subsequent insertions to the table. 

C. Column definitions cannot be altered at add DEFAULT values for columns with a NUMBER data type. 

D. All the rows that have a NULL value for the SALARY column will be updated with the value 5000. 

Answer:

Explanation: 

A change to the DEFAULT value affects only subsequent insertions to the table. Existing 

rows will not be affected. 

Incorrect Answers 

A:Column definitions can be altered to add DEFAULT values. 

C:Column definitions can be altered to add DEFAULT values. It works for columns with a 

NUMBER data type also. 

D:A change to the DEFAULT value affects only subsequent insertions to the table. Existing rows will not be affected. 

OCP Introduction to Oracle 9i: SQL Exam Guide, Jason Couchman, p. 219-224 Chapter 5: Creating Oracle Database Objects 

Q4. - (Topic 1) 

The user Alice wants to grant all users query privileges on her DEPT table. Which SQL statement accomplishes this? 

A. GRANT select ON dept TO ALL_USERS; 

B. GRANT select ON dept TO ALL; 

C. GRANT QUERY ON dept TO ALL_USERS 

D. GRANT select ON dept TO PUBLIC; 

Answer:

Explanation: view the columns associated with the constraint names in the USER_CONS_COLUMNS view. 

Incorrect Answer: Atable to view all constraints definition and names Bshow all object name belong to user Cdoes not display column associated Eno such view 

Refer: Introduction to Oracle9i: SQL, Oracle University Study Guide, 10-25 

Q5. - (Topic 2) 

What are two reasons to create synonyms? (Choose two.) 

A. You have too many tables. 

B. Your tables names are too long. 

C. Your tables have difficult names. 

D. You want to work on your own tables. 

E. You want to use another schema's tables. 

F. You have too many columns in your tables. 

Answer: B,C 

Explanation: 

Create a synonyms when the names of the tables are too long or the table names are difficult. 

Q6. - (Topic 2) 

Examine the structure of the ORDERS table: 

You want to find the total value of all the orders for each year and issue the following command: 

SQL>SELECT TO_CHAR(order_date,'rr'), SUM(order_total) 

FROM orders 

GROUP BY TO_CHAR(order_date,'yyyy'); 

Which statement is true regarding the outcome? 

A. It executes successfully and gives the correct output. 

B. It gives an error because the TO_CHAR function is not valid. 

C. It executes successfully but does not give the correct output. 

D. It gives an error because the data type conversion in the SELECT list does not match the data type conversion in the GROUP BY clause. 

Answer:

Q7. - (Topic 2) 

You want to display the date for the first Monday of the next month and issue the following command: 

SQL>SELECT TO_CHAR(NEXT_DAY(LAST_DAY(SYSDATE),'MON'), 'dd "is the first Monday for"fmmonth rrrr') FROM DUAL; 

What is the outcome? 

A. It executes successfully and returns the correct result. 

B. It executes successfully but does not return the correct result. 

C. It generates an error because TO_CHAR should be replaced with TO_DATE. 

D. It generates an error because rrrr should be replaced by rr in the format string. 

E. It generates an error because fm and double quotation marks should not be used in the format string. 

Answer:

Explanation: 

NEXT_DAY(date, 'char'): Finds the date of the next specified day of the week ('char') following date. The value of char may be a number representing a day or a character string. 

LAST_DAY(date): Finds the date of the last day of the month that contains date The second innermost function is evaluated next. TO_CHAR('28-OCT-2009', 'fmMonth') converts the given date based on the Month format mask and returns the character string October. The fm modifier trims trailing blank spaces from the name of the month. 

Q8. - (Topic 2) 

View the Exhibit and examine the data in the PROMO_CATEGORY and PROMO_COST columns of the PROMOTIONS table. 

Evaluate the following two queries: 

SQL>SELECT DISTINCT promo_category to_char(promo_cost)"code" 

FROM promotions 

ORDER BY code; 

SQL>SELECT DISTINCT promo_category promo_cost "code" 

FROM promotions 

ORDER BY 1; 

Which statement is true regarding the execution of the above queries? 

A. Only the first query executes successfully. 

B. Only the second query executes successfully. 

C. Both queries execute successfully but give different results. 

D. Both queries execute successfully and give the same result. 

Answer:

Explanation: 

Note: You cannot use column alias in the WHERE clause. 

Q9. - (Topic 1) 

Which statement correctly describes SQL and /SQL*Plus? 

A. Both SQL and /SQL*plus allow manipulation of values in the database. 

B. /SQL*Plus recognizes SQL statements and sends them to the server; SQL is the Oracle proprietary interface for executing SQL statements. 

C. /SQL*Plus is a language for communicating with the Oracle server to access data; SQL recognizes SQL statements and sends them to the server. 

D. SQL manipulates data and table definitions in the database; /SQL*Plus does not allow manipulation of values in the database. 

Answer:

Q10. - (Topic 1) 

View the Exhibit and examine the structure of the PROMOTIONS, SALES, and CUSTOMER tables. 

You need to generate a report showing the promo name along with the customer name for all products that were sold during their promo campaign and before 30th October 2007. 

You issue the following query: 

Which statement is true regarding the above query? 

A. It executes successfully and gives the required result. 

B. It executes successfully but does not give the required result. 

C. It produces an error because the join order of the tables is incorrect. 

D. It produces an error because equijoin and nonequijoin conditions cannot be used in the same SELECT statement. 

Answer:

Q11. - (Topic 2) 

Examine the structure proposed for the TRANSACTIONS table: 

Which two statements are true regarding the storage of data in the above table structure? (Choose two.) 

A. The TRANS_DATE column would allow storage of dates only in the dd-mon-yyyy format. 

B. The CUST_CREDIT_VALUE column would allow storage of positive and negative integers. 

C. The TRANS_VALIDITY column would allow storage of a time interval in days, hours, minutes, and seconds. 

D. The CUST_STATUS column would allow storage of data up to the maximum VARCHAR2 size of 4,000 characters. 

Answer: B,D 

Explanation: 

B: The NUMBER datatype stores fixed and floating-point numbers. Numbers of virtually 

any magnitude can be stored and are guaranteed portable among different systems 

operating Oracle, up to 38 digits of precision. 

The following numbers can be stored in a NUMBER column: 

Positive numbers in the range 1 x 10-130 to 9.99...9 x 10125 with up to 38 significant digits Negative numbers from -1 x 10-130 to 9.99...99 x 10125 with up to 38 significant digits Zero Positive and negative infinity (generated only by importing from an Oracle Version 5 database) 

D: The VARCHAR2 datatype stores variable-length character strings. When you create a table with a VARCHAR2 column, you specify a maximum string length (in bytes or characters) between 1 and 4000 bytes for the VARCHAR2 column. An interval literal specifies a period of time, and Oracle supports two types of interval literals: YEAR_TO_MONTH and DAY TO SECOND. For DAY TO SECOND, you can specify these differences in terms in terms of days, hours, minutes, and seconds. DAY TO SECOND contains a leading field and may contain an optional trailing field. If trailing field is specified it must be less significant than the leading field. For example, INTERVAL MINUTE TO DAY is not valid. 

A DAY TO MINUTE interval considers an interval of days to the nearest minute. Reference: Oracle Database Concepts 10g, Native Datatypes 

Q12. - (Topic 2) 

EMPLOYEES and DEPARTMENTS data: EMPLOYEES 

DEPARTMENTS 

On the EMPLOYEES table, EMPLOYEE_ID is the primary key. MGR_ID is the ID managers and refers to the EMPLOYEE_ID. 

On the DEPARTMENTS table DEPARTMENT_ID is the primary key. 

Evaluate this UPDATE statement. 

UPDATE employees SET mgr_id = (SELECT mgr_id FROMemployees WHERE dept_id= (SELECT department_id FROM departments WHERE department_name = 'Administration')), Salary = (SELECT salary 

FROM employees 

WHERE emp_name = 'Smith') 

WHERE job_id = 'IT_ADMIN' 

What happens when the statement is executed? 

A. The statement executes successfully, leaves the manager ID as the existing value, and changes the salary to 4000 for the employees with ID 103 and 105. 

B. The statement executes successfully, changes the manager ID to NULL, and changes the salary to 4000 for the employees with ID 103 and 105. 

C. The statement executes successfully, changes the manager ID to NULL, and changes the salary to 3000 for the employees with ID 103 and 105. 

D. The statement fails because there is more than one row matching the employee name Smith. 

E. The statement fails because there is more than one row matching the IT_ADMIN job ID in the EMPLOYEES table. 

F. The statement fails because there is no 'Administration' department in the DEPARTMENTS table. 

Answer:

Explanation: 

'=' is use in the statement and sub query will return more than one row. 

Employees table has 2 row matching the employee name Smith. 

The update statement will fail. 

Incorrect Answers : 

A. The Update statement will fail no update was done. 

B. The update statement will fail no update was done. 

C. The update statement will fail no update was done. 

E. The update statement will fail but not due to job_it='IT_ADMIN' 

F. The update statement will fail but not due to department_id='Administration' 

Refer: Introduction to Oracle9i: SQL, Oracle University Student Guide, Sub queries, p. 6-12 

Q13. - (Topic 2) 

View the Exhibits and examine PRODUCTS and SALES tables. 

You issue the following query to display product name and the number of times the product has been sold: 

SQL>SELECT p.prod_name, i.item_cnt FROM (SELECT prod_id, COUNT(*) item_cnt FROM sales GROUP BY prod_id) i RIGHT OUTER JOIN products p 

ON i.prod_id = p.prod_id; 

What happens when the above statement is executed? 

A. The statement executes successfully and produces the required output. 

B. The statement produces an error because ITEM_CNT cannot be displayed in the outer query. 

C. The statement produces an error because a subquery in the FROM clause and outer-joins cannot be used together. 

D. The statement produces an error because the GROUP BY clause cannot be used in a subquery in the FROM clause. 

Answer:

Q14. - (Topic 1) 

The STUDENT_GRADES table has these columns: 

Which statement finds students who have a grade point average (GPA) greater than 3.0 for the calendar year 2001? 

A. SELECT student_id, gpa 

FROM student_grades 

WHERE semester_end BETWEEN ’01-JAN-2001’ AND ’31-DEC-2001’ 

OR gpa > 3.; 

B. SELECT student_id, gpa 

FROM student_grades 

WHERE semester_end BETWEEN ’01-JAN-2001’ AND ’31-DEC-2001’ 

AND gpa gt 3.0; 

C. SELECT student_id, gpa 

FROM student_grades 

WHERE semester_end BETWEEN ’01-JAN-2001’ AND ’31-DEC-2001’ 

AND gpa > 3.0; 

D. SELECT student_id, gpa 

FROM student_grades 

WHERE semester_end BETWEEN ’01-JAN-2001’ AND ’31-DEC-2001’ 

OR gpa > 3.0; 

E. SELECT student_id, gpa 

FROM student_grades 

WHERE semester_end > ’01-JAN-2001’ OR semester_end < ’31-DEC-2001’ 

AND gpa >= 3.0; 

Answer:

Q15. - (Topic 2) 

The CUSTOMERS table has these columns: 

A promotional sale is being advertised to the customers in France. Which WHERE clause identifies customers that are located in France? 

A. WHERE lower(country_address) = "france" 

B. WHERE lower(country_address) = 'france' 

C. WHERE lower(country_address) IS 'france' 

D. WHERE lower(country_address) = '%france%' 

E. WHERE lower(country_address) LIKE %france% 

Answer:

Explanation: 

WHERE lower(country_address)=’france’ 

Incorrect Answer: Ainvalid use of symbol “” Cinvalid use of IS keyword Dinvalid use of % in condition Einvalid use of condition Refer: Introduction to Oracle9i: SQL, Oracle University Study Guide, 2-12 

START 1Z0-051 EXAM